11/1/2023 0 Comments Soda can![]() ![]() (c) As x decreases the center of mass of the soda in the can at first drops, then rises to H / 2 = 6. 0 c m above the base, on the cylinder axis. ![]() H = M + m M ( H / 2 ) + m ( H / 2 ) = 2 H Ībove the base, on the cylinder axis. Thus the center of mass of the can and the soda it contains is a distance ![]() The center of mass of the soda alone is at its geometrical center, a distance x / 2 above the base of the can. (a) Since the can is uniform, its center of mass is at its geometrical center, a distance H / 2 above its base.
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